Returns a string, which is a substring of a string expression beginning at the start position (defaults to 1), in which a specified substring has been replaced with another substring a specified number of times.
Syntax
Replace(expression, find, replace, [ start, [ count, [ compare ]]])
The Replace function syntax has these named arguments:
Part | Description |
---|---|
expression | Required. String expression containing substring to replace. |
find | Required. Substring being searched for. |
replace | Required. Replacement substring. |
start | Optional. Start position for the substring of expression to be searched and returned. If omitted, 1 is assumed. |
count | Optional. Number of substring substitutions to perform. If omitted, the default value is -1, which means, make all possible substitutions. |
compare | Optional. Numeric value indicating the kind of comparison to use when evaluating substrings. See Settings section for values. |
Settings
The compare argument can have the following values:
Constant | Value | Description |
---|---|---|
vbUseCompareOption | -1 | Performs a comparison by using the setting of the Option Compare statement. |
vbBinaryCompare | 0 | Performs a binary comparison. |
vbTextCompare | 1 | Performs a textual comparison. |
vbDatabaseCompare | 2 | Microsoft Access only. Performs a comparison based on information in your database. |
Return values
Replace returns the following values:
If | Replace returns |
---|---|
expression is zero-length | Zero-length string ("") |
expression is Null | An error. |
find is zero-length | Copy of expression. |
replace is zero-length | Copy of expression with all occurrences of find removed. |
start > Len(expression) | Zero-length string. String replacement begins at the position indicated by start. |
count is 0 | Copy of expression. |
Remarks
The return value of the Replace function is a string, with substitutions made, that begins at the position specified by start and concludes at the end of the expression string. It's not a copy of the original string from start to finish.
Examples
The following example replaces "
"(space) with "+
"
Dim Keywords As String
Dim SearchString As String
SearchString = Replace(Keywords, " ", "+")