Returns a Range object that represents the columns in the specified range.
expression A variable that represents a Range object.
To return a single column, use the Item property or equivalently include an index in parentheses. For example, both
Selection.Columns.Item(1) return the first column of the selection.
When applied to a Range object that is a multiple-area selection, this property returns columns from only the first area of the range. For example, if the Range object has two areas—A1:B2 and C3:D4—
Selection.Columns.Count returns 2, not 4. To use this property on a range that may contain a multiple-area selection, test
Areas.Count to determine whether the range contains more than one area. If it does, loop over each area in the range.
The returned range might be outside the specified range. For example,
Range("A1:B2").Columns(5).Select returns cells E1:E2.
If a letter is used as an index, it is equivalent to a number. For example,
Range("B1:C10").Columns("B").Select returns cells C1:C10, not cells B1:B10. In the example, "B" is equivalent to 2.
Using the Columns property without an object qualifier is equivalent to using
ActiveSheet.Columns. For more information, see the Worksheet.Columns property.
This example sets the value of every cell in column one in the range named myRange to 0 (zero).
Range("myRange").Columns(1).Value = 0
This example displays the number of columns in the selection on Sheet1. If more than one area is selected, the example loops through each area.
Public Sub ShowNumberOfColumnsInSheet1Selection() Worksheets("Sheet1").Activate Dim selectedRange As Excel.Range Set selectedRange = Selection Dim areaCount As Long areaCount = Selection.Areas.count If areaCount <= 1 Then MsgBox "The selection contains " & _ Selection.Columns.count & " columns." Else Dim areaIndex As Long areaIndex = 1 For Each area In Selection.Areas MsgBox "Area " & areaIndex & " of the selection contains " & area.Columns.count & " columns." areaIndex = areaIndex + 1 Next End If End Sub